The frequency distribution of the age of students in a class of 40 students is given below. [figure] If the mean deviation about the median is 1.25, then 4x + 5y is equal to :
- 43
- 46
- 44
- 47
Answer
(3) 44
Solution
Total = 40 30 + x + y = 40 x + y = 10 …(i)
Cumulative frequencies: 5, 13, 18, 30, … so the 20th and 21st observations are both 18, hence median M = 18
M.D. = fi|xi - 18|40 = 5(3) + 8(2) + 5(1) + 12(0) + x(1) + y(2)40 = 1.25
36 + x + 2y = 50 x + 2y = 14 …(ii)
From (i) and (ii): y = 4, x = 6, so 4x + 5y = 24 + 20 = 44
Answer: (3)