A particle of charge q and mass m is projected from origin with an initial velocity v= ( v0 2 x+ v0 2 y ). There exists a uniform magnetic field B=B0 z and a space varying electric field E=E0e- x x within the region 0 x L. After travelling a distance such that x-coordinate has changed from x=0 to x=L, the change in the kinetic energy is .
- qE0 [1-e- L ]
- ( v0qB02 ) [2-e-2 L ]
- qE0 [1+e- L ]
- q ( E0+v0B0 ) [1-e- L/2 ]
Answer
(1) qE0 [1-e- L ]
Solution
Magnetic force q v B is always perpendicular to v it does no work.
Work–energy theorem: K=WE= FE d r
E is along x only dx matters:
K= 0L qE0e- x dx=qE0 [- e- x ]0L
K= qE0 [1-e- L ]
Answer: (1)