The charged particle moving in a uniform magnetic field of (3 i+2 j ) T has an acceleration (4 i- x2 j ) m/s2. The value of x is .
Answer
12
Solution
F=q v B ⇒ F B ⇒ a B
∴ a B=0
⇒ (4 i- x2 j ) (3 i+2 j )=0
⇒ 12-x=0
∴ x=12
Answer: 12
The charged particle moving in a uniform magnetic field of (3 i+2 j ) T has an acceleration (4 i- x2 j ) m/s2. The value of x is .
12
F=q v B ⇒ F B ⇒ a B
∴ a B=0
⇒ (4 i- x2 j ) (3 i+2 j )=0
⇒ 12-x=0
∴ x=12
Answer: 12
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