A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle ' ' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, , is then given by :
- = -1 ( 2gT2 2 R )1/2
- = -1 ( gT2 2 R )1/2
- = -1 ( 2 RgT2 )1/2
- = -1 ( 2 RgT2 )1/2
Answer
(1) = -1 ( 2gT2 2 R )1/2
Solution
Speed of the particle: u = 2 RT
Maximum height of the projectile:
H = u2 2 2g = 4R
4 2R2T2 2 2g = 4R
2 = 8gRT24 2R2 = 2gT2 2 R
= -1 ( 2gT2 2 R )1/2
Answer: (1)