A car starts from rest and accelerates at 5 m/s2. At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s2)
- 20 2 m/s, 10 m/s2
- 20 m/s, 5 m/s2
- 20 m/s, 0
- 20 2 m/s, 0
Answer
(1) 20 2 m/s, 10 m/s2
Solution
Velocity of the car at t = 4 s: vx = at = 5 4 = 20 m/s
After release the ball keeps this horizontal velocity (no horizontal force), and only gravity acts on it.
At t = 6 s (i.e. 2 s after release):
vy = gt' = 10 2 = 20 m/s
v = vx2 + vy2 = 202 + 202 = 20 2 m/s
Acceleration of the ball = g = 10 m/s2 (vertically downward)
Answer: (1)