Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is T1 and that at the right junction is T2. The ratio T1/T2 is [figure]
- 53
- 54
- 32
- 43
Answer
(1) 53
Solution
Thermal resistance of a rod: R = lkA. Let R0 = lKA.
Side rods: R1 = R3 = R02; middle rod: R2 = R0.
Total resistance: R = R02 + R0 + R02 = 2R0
Heat current (same through every rod in steady state): H = 3T - T2R0 = TR0
T1 = 3T - H R1 = 3T - T2 = 5T2
T2 = T + H R3 = T + T2 = 3T2
T1T2 = 5T/23T/2 = 53
Answer: (1)