The hybridization involved in complex [Ni(CN)4]2- is (At. No. Ni = 28)
- sp3
- d2sp2
- d2sp3
- dsp2
Answer
(4) dsp2
Solution
Oxidation state of Ni: x + 4(-1) = -2 ⇒ x = +2
Ni2+ (Z = 28): [Ar] 3d8
∵ CN- is a strong field ligand, the two unpaired 3d electrons pair up and one 3d orbital becomes empty.
⇒ One 3d, one 4s and two 4p orbitals hybridise: dsp2 (square planar, diamagnetic).
As per NCERT, [Ni(CN)4]2- is square planar with dsp2 hybridisation.
Answer: (4)