Consider |x| is the difference in oxidation states of Mn in highest manganese fluoride and highest manganese oxide. The ions with |x| number of unpaired electrons from the following are : Choose the correct answer from the options given below :
- A and B Only
- C, D and E Only
- C and E Only
- B and E Only
Answer
(3) C and E Only
Solution
Highest manganese fluoride: MnF4 ⇒ Mn = +4
Highest manganese oxide: Mn2O7 ⇒ Mn = +7 (oxygen stabilises the higher state by forming multiple bonds)
⇒ |x| = 7 − 4 = 3 ⇒ ions with 3 unpaired electrons are required
A. Sc3+: 3d0 → 0
B. Zn2+: 3d10 → 0
C. V2+: 3d3 → 3 ✓
D. Fe2+: 3d6 → 4
E. Co2+: 3d7 → 3 ✓
∴ C and E
Answer: (3)