In the following reaction, the product (A) is [figure]
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Answer
(4) [figure]
Solution
Benzenediazonium chloride is a weak electrophile; it couples with the activated ring of aniline at the para position (azo coupling, electrophilic substitution).
As per NCERT, benzenediazonium chloride reacts with aniline in mildly acidic medium to give p-aminoazobenzene, a yellow dye:
C6H5N2+Cl- + C6H5NH2 H+ C6H5-N=N-C6H4-NH2 + HCl
∴ (A) is p-aminoazobenzene, i.e. the -NH2 group para to the -N=N- link.
Answer: (4)