Let f:R be a function given by f(x)= cases 1- 2xx2, & x<0\ , & x=0,\ 1- xx, & x>0 cases where , . If f is continuous at x=0, then 2+ 2 is equal to :
- 48
- 6
- 3
- 12
Answer
(4) 12
Solution
LHL = x 0- 1- 2xx2= x 0- 2 2xx2=2
RHL = x 0+ 2 2 x2x= x 0+ 2 x2x= 2
( x2>0 for small x>0)
Continuity: =2= 2 =2 2
2+ 2=4+8=12
Answer: (4)