At T(K), 100 g of 98\% H2SO4 (w/w) aqueous solution is mixed with 100 g of 49\% H2SO4 (w/w) aqueous solution. What is the mole fraction of H2SO4 in the resultant solution? (Given : Atomic mass H = 1 u; S = 32 u; O = 16 u). (Assume that temperature after mixing remains constant)
- 0.9
- 0.663
- 0.1
- 0.337
Answer
(4) 0.337
Solution
Molar mass: H2SO4 = 98 g mol-1, H2O = 18 g mol-1
Solution 1: H2SO4 = 98 g = 1 mol; water = 2 g
Solution 2: H2SO4 = 49 g = 0.5 mol; water = 51 g
Total: H2SO4 = 1.5 mol; water = 53 g = 5318 = 2.944 mol
xH2SO4 = 1.51.5 + 2.944 = 1.54.444 = 0.337
Answer: (4)