14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K. Which of the following statements is incorrect? [Given : Molar mass in g mol-1 of Ca – 40, Cl – 35.5, H – 1]
- The limiting reagent is calcium metal.
- 33.3 g of CaCl2 is produced.
- 7.84 L of H2 gas is evolved.
- 0.35 mol of H2 gas is evolved.
Answer
(2) 33.3 g of CaCl2 is produced.
Solution
Ca + 2HCl CaCl2 + H2
Moles of Ca = 14.040 = 0.35 mol; HCl is in excess Ca is the limiting reagent. (1) is correct.
Moles of CaCl2 = moles of H2 = 0.35 mol. (4) is correct.
Molar mass of CaCl2 = 40 + 2 35.5 = 111 g mol-1
mass of CaCl2 = 0.35 111 = 38.85 g, not 33.3 g. (2) is incorrect.
Volume of H2 at 273 K, 1 atm = 0.35 22.4 = 7.84 L. (3) is correct.
Answer: (2)