A monochromatic light of frequency 5 1014 Hz travelling through air, is incident on a medium of refractive index '2'. Wavelength of the refracted light will be:
- 400 nm
- 300 nm
- 600 nm
- 500 nm
Answer
(2) 300 nm
Solution
Wavelength in air: 0 = c = 3 1085 1014 = 6 10-7 m = 600 nm
On refraction the frequency does not change, while the speed becomes c
= 0 = 6002 = 300 nm
Answer: (2)