[figure] A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is : (C is the center of curvature of the spherical surface and R is the radius of curvature)
- 0.24 m left to the spherical surface
- 0.24 m right to the spherical surface
- 0.4 m left to the spherical surface
- 0.4 m right to the spherical surface
Answer
(3) 0.4 m left to the spherical surface
Solution
Refraction at a spherical surface: n2v - n1u = n2 - n1R
Light travels left to right (from O). Sign convention (distances from the pole, positive to the right):
n1 = 1, n2 = 1.5, u = -0.2 m, R = +0.4 m (C is on the right)
1.5v - 1-0.2 = 1.5 - 10.4
1.5v = 1.25 - 5 = -3.75
v = -0.4 m
The (virtual) image is 0.4 m to the left of the spherical surface.
Answer: (3)