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Some Basic Concepts of Chemistry · Question 6

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1

Dalton's Atomic theory could not explain which of the following?

  1. Law of multiple proportion
  2. Law of gaseous volume
  3. Law of conservation of mass
  4. Law of constant proportion

Answer

(2) Law of gaseous volume

Solution

As per NCERT, Dalton's atomic theory could explain the laws of chemical combination (conservation of mass, constant proportions and multiple proportions), because atoms are neither created nor destroyed and combine in fixed, simple whole-number ratios.

However, it could not explain the law of gaseous volumes (Gay-Lussac).

∵ e.g. 1 volume H2 + 1 volume Cl2 → 2 volumes HCl; with indivisible atoms each HCl would need half an atom of H and Cl. This was explained later by Avogadro's idea of molecules.

Answer: (2)

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2

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to

  1. 750 mg
  2. 250 mg
  3. Zero mg
  4. 200 mg
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3

The highest number of helium atoms is in

  1. 4 mol of helium
  2. 4u of helium
  3. 4 g of helium
  4. 2.271098 L of helium at STP
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4

A compound X contains 32\% of A, 20\% of B and remaining percentage of C. Then, the empirical formula of X is : (Given atomic masses of A=64 ; B=40 ; C=32 u)

  1. A2BC2
  2. ABC3
  3. AB2C2
  4. ABC4
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5

The amount of glucose required to prepare 250 mL of M20 aqueous solution is : (Molar mass of glucose : 180 g mol-1)

  1. 2.25 g
  2. 4.5 g
  3. 0.44 g
  4. 1.125 g
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6

1.0 g of H2 has same number of molecules as in:

  1. 14 g of N2
  2. 18 g of H2O
  3. 16 g of CO
  4. 28 g of N2
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7

The right option for the mass of CO2 produced by heating 20 g of 20\% pure limestone is (Atomic mass of Ca = 40) [ CaCO3 1200 K CaO + CO2]

  1. 1.76 g
  2. 2.64 g
  3. 1.32 g
  4. 1.12 g
NEET (UG) 2023
8

In one molal solution that contains 0.5 mole of a solute, there is

  1. 500 mL of solvent
  2. 500 g of solvent
  3. 100 mL of solvent
  4. 1000 g of solvent
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9

What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? CaCO3(s) + 2HCl(aq) CaCl2(aq) + CO2(g) + 2H2O(l) [Calculate upto second place of decimal point]

  1. 1.25 g
  2. 1.32 g
  3. 3.65 g
  4. 9.50 g
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10

The density of the solution is 2.15 g mL-1, then mass of 2.5 mL solution in correct significant figures is :

  1. 53.75 g
  2. 5375 10-3 g
  3. 5.4 g
  4. 5.38 g
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11

An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is : [Atomic wt. of C is 12, H is 1]

  1. CH4
  2. CH
  3. CH2
  4. CH3
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