An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is : [Atomic wt. of C is 12, H is 1]
- CH4
- CH
- CH2
- CH3
Answer
(4) CH3
Solution
Mass % of H = 100 - 78 = 22\%
Moles of C = 7812 = 6.5; moles of H = 221 = 22
⇒ C : H = 6.56.5 : 226.5 = 1 : 3.38 1 : 3
∴ empirical formula = CH3
Answer: (4)