A compound X contains 32\% of A, 20\% of B and remaining percentage of C. Then, the empirical formula of X is : (Given atomic masses of A=64 ; B=40 ; C=32 u)
- A2BC2
- ABC3
- AB2C2
- ABC4
Answer
(2) ABC3
Solution
Percentage of C = 100 - 32 - 20 = 48\%
Moles: A = 3264 = 0.5; B = 2040 = 0.5; C = 4832 = 1.5
Simplest ratio A : B : C = 0.5 : 0.5 : 1.5 = 1 : 1 : 3
Empirical formula = ABC3
Answer: (2)