An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3 Ω, the phase difference between the applied voltage and the current in the circuit is
- /6
- /4
- /2
- zero
Answer
(2) /4
Solution
For a series LR circuit, tan = XLR
tan = 33 = 1
= 4
Answer: (2)