A normal-visioned man whose father was colour-blind, marries a woman whose father was also colour-blind. They have their first child as a daughter. What are the chances that this child would be colour-blind ?
- 50%
- 25%
- 100%
- Zero percent
Answer
(4) Zero percent
Solution
Colour blindness is an X-linked recessive trait.
Man has normal vision ⇒ his genotype is XCY (his father's colour-blind X does not pass to a son).
Woman's father was colour-blind ⇒ she receives Xc from him, so she is a carrier XCXc.
Daughters = XC (from father) ( XC or Xc from mother) = XCXC or XCXc
∴ Every daughter receives the normal X from the father, so no daughter can be colour-blind (half may be carriers).
Answer: (4)