Distance between object and its image (magnified by - 13) is 30 cm. The focal length of the mirror used is ( x4 )cm, where magnitude of value of x is .
Answer
45
Solution
m = - 13 (real, inverted, diminished) concave mirror, object beyond 2F; object and image on the same side.
m = - vu = - 13 v = u3, i.e. |v| = |u|3
Distance between them: |u| - |v| = 30 2|u|3 = 30 |u| = 45 cm, |v| = 15 cm
With u = -45 cm, v = -15 cm:
1f = 1v + 1u = - 115 - 145 = - 445
f = - 454 cm = x4 cm x = -45
|x| = 45
Answer: 45