A point charge of 10-8 C is placed at origin. The work done in moving a point charge 2 from point A(4, 4, 2) m to B(2, 2, 1) m is J. ( 14 0 = 9 109 in SI units)
- 30 10-6
- 0
- 15 10-6
- 45 10-6
Answer
(1) 30 10-6
Solution
Distances of A and B from the charge at the origin:
rA = 42 + 42 + 22 = 6 m, rB = 22 + 22 + 12 = 3 m
VA = 14 0 QrA = 9 109 10-86 = 15 V
VB = 9 109 10-83 = 30 V
Work done in moving the charge q from A to B:
W = q(VB - VA) = 2 10-6 (30 - 15)
W = 30 10-6 J
Answer: (1)