0.1 mol of the following given antiviral compound (P) will weigh 10-1 g (nearest integer). [figure] (Given : molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, F : 19, I : 127)
Answer
372
Solution
Counting the atoms of (P):
Base ring (5-iodouracil part): 4 C, 2 N, 2 O, 1 I and 2 H (N–H and C6–H)
Sugar part: 5 C, 3 O (ring O and two –OH), 1 F and 8 H (C1′–H, C2′–H, C3′–H, C4′–H, CH2 (2 H), two O–H)
Molecular formula of P = C9H10FIN2O5
Molar mass = 9(12) + 10(1) + 19 + 127 + 2(14) + 5(16)
= 108 + 10 + 19 + 127 + 28 + 80 = 372 g mol-1
Mass of 0.1 mol = 0.1 372 = 37.2 g = 372 10-1 g
Answer: 372