On complete combustion 1.0 g of an organic compound (X) gave 1.46 g of CO2 and 0.567 g of H2O. The empirical formula mass of compound (X) is g. (Given molar mass in g mol-1 C : 12, H : 1, O : 16)
- 60
- 45
- 30
- 15
Answer
(3) 30
Solution
Mass of C = 1244 1.46 = 0.398 g
Mass of H = 218 0.567 = 0.063 g
Mass of O = 1.0 - (0.398 + 0.063) = 0.539 g
Moles: C = 0.39812 = 0.0332, H = 0.0631 = 0.063, O = 0.53916 = 0.0337
Simplest ratio C : H : O 1 : 2 : 1
Empirical formula = CH2O
Empirical formula mass = 12 + 2 + 16 = 30 g
Answer: (3)