A particle is rotating in a circular path and at any instant its motion can be described as = 5t440- t33. The angular acceleration of the particle after 10 seconds is rad/s2.
- 150
- 120
- 130
- 170
Answer
(3) 130
Solution
= 5t440- t33= t48- t33
= d dt= t32-t2
= d dt= 3t22-2t
At t=10 s: = 3 1002-2 10
=150-20=130 rad/s2
Answer: (3)