Moment of inertia about an axis AB for a rod of mass 40 kg and length 3 m is same as that of a solid sphere of mass of 10 kg and radius R about an axis parallel to AB axis with separation of 3 m as shown in figure below. The value of R is given as 2. The value of is . [figure]
Answer
15
Solution
Rod about the axis AB through its end (perpendicular to the rod):
Irod = ML23 = 40 (3)23 = 120 kg m2
Sphere about its own diameter: Icm = 25mR2 = 25 10 R2 = 4R2
The axis AB is parallel to this diameter at d = 3 m, so by the parallel axis theorem:
Isphere = Icm + md2 = 4R2 + 10 (3)2 = 4R2 + 90
Equating: 4R2 + 90 = 120
⇒ 4R2 = 30 ⇒ R2 = 152 ⇒ R = 152 m
∴ = 15
Answer: 15