Two blocks of masses 2 kg and 1 kg respectively, are tied to the ends of a string which passes over a light frictionless pulley as shown in the figure below. The masses are held at rest at the same horizontal level and then released. The distance traversed by the centre of mass in 2 s is m. (Take g=10 m/s2) [figure]
- 3.33
- 3.12
- 2.22
- 1.42
Answer
(3) 2.22
Solution
Acceleration of the blocks (2 kg moves down, 1 kg moves up):
a = (m1 - m2)gm1 + m2 = (2 - 1) 103 = 103 m/s2
Taking downward as positive:
acm = m1a + m2(-a)m1 + m2 = 2a - a3 = a3 = 109 m/s2 (downward)
The system starts from rest, so the centre of mass moves in a straight line:
scm = 12acmt2 = 12 109 (2)2
⇒ scm = 209 = 2.22 m
Answer: (3)