In the circuit shown in the figure, if the potential at point A is taken to be zero, the potential at point B is [figure]
- +1 V
- -1 V
- +2 V
- -2 V
Answer
(1) +1 V
Solution
Applying Kirchhoff's junction rule at C: current 1 A enters from A and 2 A leaves towards the right, so 1 A flows from D to C through the 2 resistor.
Going from A to C through the 1 V cell (negative to positive terminal): VC = VA + 1 = 1 V
Going from C to D through the 2 resistor (against the current): VD = VC + 2 1 = 3 V
Going from D to B through the 2 V cell (positive to negative terminal): VB = VD - 2 = 1 V
VB = +1 V
Answer: (1)