If voltage across a bulb rated 220 volt-100 watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is
- 20%
- 2.5%
- 5%
- 10%
Answer
(3) 5%
Solution
For the bulb, resistance R is constant: P = V2R
P = 2 V (for a small change)
Percentage decrease in power = 2 2.5\% = 5\%
Answer: (3)