A rectangular wire loop of sides 8 cm and 3 cm with a small cut, is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the plane of the loop. The emf developed across the cut, if the velocity of the loop is 2 cm s-1, in a direction normal to the shorter side of the loop, will be :
- 1.8 10-4 volt
- 1.3 10-4 volt
- 1.2 10-4 volt
- 4.8 10-4 volt
Answer
(1) 1.8 10-4 volt
Solution
The velocity is normal to the 3 cm side, so the side cutting the field lines has l = 3 cm.
e = Blv = 0.3 0.03 0.02
e = 1.8 10-4 V
Answer: (1)