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Equilibrium · Question 89

AIPMT 2004MCQMedium📈 Topic in 25% papers+4−1
1

The rapid change of pH near the stoichiometric point of an acid-base titration is the basis of indicator detection. pH of the solution is related to ratio of the concentrations of the conjugate acid (HIn) and base (In-) forms of the indicator by the expression

  1. [In-][HIn] = pKIn - pH
  2. [HIn][In-] = pKIn - pH
  3. [HIn][In-] = pH - pKIn
  4. [In-][HIn] = pH - pKIn

Answer

(4) [In-][HIn] = pH - pKIn

Solution

The indicator is a weak acid: HIn H+ + In-

KIn = [H+][In-][HIn]

⇒ [H+] = KIn [HIn][In-]

Taking - on both sides:

pH = pKIn + [In-][HIn]

∴ [In-][HIn] = pH - pKIn

Answer: (4)

AIPMT 2004

Keep practising — Equilibrium

2

The equilibrium constants of the following are N2 + 3H2 2NH3; K1 N2 + O2 2NO; K2 H2 + 12O2 H2O; K3 The equilibrium constant (K) of the reaction : 2NH3 + 52O2 2NO + 3H2O will be

  1. K2K33/K1
  2. K2K3/K1
  3. K23K3/K1
  4. K1K33/K2
AIPMT 2003
3

The reaction quotient (Q) for the reaction N2(g) + 3H2(g) 2NH3(g) is given by Q = [NH3]2[N2][H2]3. The reaction will proceed from right to left if

  1. Q = Kc
  2. Q < Kc
  3. Q > Kc
  4. Q = 0
AIPMT 2003
4

The solubility product of AgI at 25 C is 1.0 10-16 mol2 L-2. The solubility of AgI in 10-4 N solution of KI at 25 C is approximately (in mol L-1)

  1. 1.0 10-16
  2. 1.0 10-12
  3. 1.0 10-10
  4. 1.0 10-8
AIPMT 2003
5

Reaction BaO2(s) BaO(s) + O2(g); H = +ve. In equilibrium condition, pressure of O2 depends on

  1. increase mass of BaO2
  2. increase mass of BaO
  3. increase temperature on equilibrium
  4. increase mass of BaO2 and BaO both
AIPMT 2002
6

Solubility of MX2 type electrolytes is 0.5 10-4 mole/lit., then find out Ksp of electrolytes.

  1. 5 10-12
  2. 25 10-10
  3. 1 10-13
  4. 5 10-13
AIPMT 2002
7

Which has highest pH?

  1. CH3COOK
  2. Na2CO3
  3. NH4Cl
  4. NaNO3
AIPMT 2002
8

Solution of 0.1 N NH4OH and 0.1 N NH4Cl has pH 9.25. Then find out pKb of NH4OH

  1. 9.25
  2. 4.75
  3. 3.75
  4. 8.25
AIPMT 2002
9

In HS-, I-, R-NH2, NH3 order of proton accepting tendency will be

  1. I- > NH3 > R-NH2 > HS-
  2. NH3 > R-NH2 > HS- > I-
  3. R-NH2 > NH3 > HS- > I-
  4. HS- > R-NH2 > NH3 > I-
AIPMT 2001
10

Ionisation constant of CH3COOH is 1.7 10-5 and concentration of H+ ions is 3.4 10-4. Then find out initial concentration of CH3COOH molecules.

  1. 3.4 10-4
  2. 3.4 10-3
  3. 6.8 10-4
  4. 6.8 10-3
AIPMT 2001
11

Solubility of M2S salt is 3.5 10-6 then find out solubility product.

  1. 1.7 10-6
  2. 1.7 10-16
  3. 1.7 10-18
  4. 1.7 10-12
AIPMT 2001

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