Equilibrium constants K1 and K2 for the following equilibria: NO(g) + 12O2(g) K1 NO2(g) and 2NO2(g) K2 2NO(g) + O2(g) are related as
- K2 = 1/K12
- K2 = K12
- K2 = 1/K1
- K2 = K1/2
Answer
(1) K2 = 1/K12
Solution
As per NCERT, on reversing a reaction K becomes 1/K, and on multiplying the equation by n, K becomes Kn.
Reversing the first equilibrium:
NO2(g) NO(g) + 12O2(g); K' = 1K1
Multiplying by 2:
2NO2(g) 2NO(g) + O2(g); K2 = ( 1K1 )2
∴ K2 = 1/K12
Answer: (1)