A circle is inscribed in an equilateral triangle of side of length 12. If the area and perimeter of any square inscribed in this circle are m and n, respectively, then m + n2 is equal to
- 408
- 414
- 312
- 396
Answer
(1) 408
Solution
Inradius of an equilateral triangle: r = a2 3 = 122 3 = 2 3
[figure]
the square is inscribed in the circle, its diagonal = diameter = 4 3
side a = 4 3 2 = 2 6
m = a2 = 24, n = 4a = 8 6
m + n2 = 24 + 384 = 408
Answer: (1)