Let S be the focus of the hyperbola x23 - y25 = 1, on the positive x-axis. Let C be the circle with its centre at A( 6, 5) and passing through the point S. If O is the origin and SAB is a diameter of C, then the square of the area of the triangle OSB is equal to .
Answer
40
Solution
a2 = 3, b2 = 5 ⇒ ae = a2 + b2 = 2 2 ⇒ S(2 2, 0)
∵ SB is a diameter, A is its mid-point ⇒ B = (2 6 - 2 2, 2 5)
[figure]
Area(OSB) = 12 OS (height of B) = 12 2 2 2 5 = 2 10
∴ (Area)2 = 40
Answer: 40