The ratio of solubility of AgCl in 0.1 M KCl solution to the solubility of AgCl in water is: (Given : Solubility product of AgCl = 10-10)
- 10-4
- 10-6
- 10-9
- 10-5
Answer
(1) 10-4
Solution
In water: Ksp = s2
s = 10-10 = 10-5 mol L-1
In 0.1 M KCl: [Cl-] 0.1 M (common ion)
Ksp = s' 0.1
s' = 10-100.1 = 10-9 mol L-1
s's = 10-910-5 = 10-4
Answer: (1)