Let f be a polynomial function such that 2(f(x))= ( 2 (2+ 23+ 29+ ) ) 3 (1+ f(x)f ( 1x ) ), x>0 and f(6)=37. Then n=110f(n) is equal to .
Answer
395
Solution
2+ 23+ 29+ = 21- 13=3
2 f(x)= 2 3 3 (1+ f(x)f(1/x) )= 2 (1+ f(x)f(1/x) )
f(x)=1+ f(x)f(1/x) f(x) f ( 1x )=f(x)+f ( 1x )
A polynomial satisfying this is f(x)=1 xk
f(6)=37 1+6k=37 k=2 f(x)=x2+1
n=110f(n)= n=110n2+10= 10 11 216+10=385+10=395
Answer: 395