The output (Y) of the given logic gate is similar to the output of an/a [figure]
- NAND gate
- NOR gate
- OR gate
- AND gate
Answer
(4) AND gate
Solution
NAND gate with both inputs A: Y1 = A A = A
NOR gate with both inputs B: Y2 = B + B = B
Final NOR gate: Y = Y1 + Y2 = A + B
Y = A B (De Morgan's theorem)
This is the output of an AND gate.
Answer: (4)