The output Y for the inputs A and B of the given logic circuit is: [figure]
- A B
- A B
- A + B
- A + B
Answer
(3) A + B
Solution
A NAND gate with both inputs joined acts as a NOT gate.
Outputs of the first two gates: A and B
Final NAND gate: Y = A B
By De Morgan's theorem: Y = A + B = A + B
Answer: (3)