For the following logic circuit, the truth table is: [figure]
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(1) [figure]
Solution
Outputs of the NOT gates: A and B.
NAND gate output: Y = A B
= A + B (De Morgan's theorem)
= A + B (OR gate)
Y = 0 only for A = B = 0; Y = 1 for the other three inputs, as in table (1).
Answer: (1)