A particle moving along x-axis has acceleration f, at time t, given by f = f0 (1 - tT ), where f0 and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle's velocity (vx) is
- 12f0T2
- f0T2
- 12f0T
- f0T
Answer
(3) 12f0T
Solution
f = 0 ⇒ 1 - tT = 0 ⇒ t = T
vx = 0T f dt = 0T f0 (1 - tT )dt
= f0 [t - t22T ]0T
= f0 (T - T2 )
∴ vx = 12f0T
Answer: (3)