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The current in an inductor is given by I = (3t + 8) where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The self-inductance of the inductor mH.
4
| | = L dIdt, with dIdt = 3 A/s
L = 12 10-33 = 4 10-3 H
= 4 mH
Answer: 4
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