A rod of length 60 cm rotates with a uniform angular velocity 20 rad s-1 about its perpendicular bisector, in a uniform magnetic field 0.5 T. The direction of magnetic field is parallel to the axis of rotation. The potential difference between the two ends of the rod is V.
Answer
0
Solution
EMF between centre O and each end: = 12B ( L2 )2 (L = 0.6 m)
= 12 0.5 20 (0.3)2 = 0.45 V
both halves are identical and symmetric about O, VO - VP = VO - VQ = 0.45 V (P, Q = ends)
VP - VQ = 0
Answer: 0