If three successive terms of a G.P. with common ratio r(r>1) are the lengths of the sides of a triangle and [r] denotes the greatest integer less than or equal to r, then 3[r]+[-r] is equal to .
Answer
1
Solution
Sides a, ar, ar2 (r>1, so ar2 is the largest side)
sum of the two smaller sides > largest side: a+ar>ar2
r2-r-1<0 1<r< 1+ 52 1.618
(The other two inequalities hold for every r>1.)
[r]=1, [-r]=-2
3[r]+[-r]=3-2=1
Answer: 1