Let Sn denote the sum of the first n terms of an arithmetic progression. If S10=390 and the ratio of the tenth and the fifth terms is 15:7, then S15-S5 is equal to :
- 800
- 890
- 790
- 690
Answer
(3) 790
Solution
S10=5(2a+9d)=390 2a+9d=78 ...(i)
a+9da+4d= 157 7a+63d=15a+60d 3d=8a ...(ii)
(i), (ii) 2a+24a=78 a=3, d=8
S15-S5=t6+t7+ +t15 (10 terms)
= 102 (t6+t15 )=5(43+115)=790
Answer: (3)