[figure] N equally spaced charges each of value q, are placed on a circle of radius R. The circle rotates about its axis with an angular velocity as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, IA-IB, for the given Amperian loops is
- N22 q
- N2 q
- 2 Nq
- N q
Answer
(2) N2 q
Solution
Current = net charge crossing the loop's surfaceperiod, T= 2 .
Loop A is cut once by the ring: all N charges cross it each revolution IA= NqT= Nq 2
Loop B is cut twice, charges crossing in opposite senses net charge 0 IB=0
IA-IB= N2 q
Answer: (2)