A current of 5 A exists in a square loop of side 1 2 m. Then the magnitude of the magnetic field B at the centre of the square loop will be p 10-6 T. where, value of p is [Take 0=4 10-7 T m A-1].
Answer
8
Solution
Each side is a finite wire at distance d= L2= 12 2 m; all four fields point the same way at O.
[figure]
Bside= 0I4 d ( 45 + 45 )=10-7 5 2 2 2=2 10-6 T
B=4Bside=8 10-6 T p=8
Answer: 8