The mean free path of molecules in an ideal gas A is half that of another ideal gas B. The diameter of the spherical molecules of gas A is twice the diameter of the molecules of B. If number densities of the gases A and B are nA and nB, respectively, the correct option is:
- nA = 12 nB
- nA = nB
- nA = 2nB
- nA = 14 nB
Answer
(1) nA = 12 nB
Solution
The mean free path of gas molecules is given by:
= 1 2 d2 n n 1 d2
Therefore:
nAnB = ( B A ) ( dBdA )2
Given A = 12 B and dA = 2dB:
nAnB = (2) ( 12 )2 = 2 14 = 12 nA = 12 nB
Answer: (1)