Coordination Compounds · Question 8

The total number of unpaired electrons present in the d3, d4 (low spin) d5 (high spin), d6 (high spin) and d7 (low spin) octahedral complex systems is .

Consider the metal complexes [Ni(en)3]2+ (A), [NiCl4]2- (B) and [Ni(NH3)6]2+ (C). Choose the CORRECT option by considering the number of unpaired electrons present in (A), (B) and (C) respectively and the order of frequency of absorption.

1. 2, 2, 2 and (A) > (C) > (B)
2. 0, 2, 0 and (A) > (C) > (B)
3. 2, 2, 0 and (B) > (C) > (A)
4. 2, 2, 2 and (C) > (A) > (B)

Match List - I with List - II.

1. A-I, B-II, C-III, D-IV
2. A-II, B-III, C-IV, D-I
3. A-III, B-IV, C-I, D-II
4. A-IV, B-I, C-II, D-III

5.33 g of CrCl3 6H2O, which is a 1 : 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with AgNO3 results in 8.61 g of AgCl. The ratio of moles of complex reacted and moles of AgCl formed is 10-2. (Nearest integer) [Molar mass in g mol-1 Cr : 52, Ag : 108, Cl : 35.5, H : 1, O : 16]

Which of the following complexes will show coordination isomerism? Choose the correct answer from the options given below:

1. B, C and D Only
2. B, D and E Only
3. A, C and D Only
4. C, D and E Only

The correct statement among the following is:

1. [Ni(CN)4]2- and [NiCl4]2- are diamagnetic and Ni(CO)4 is paramagnetic.
2. Ni(CO)4 is diamagnetic and [NiCl4]2- and [Ni(CN)4]2- are paramagnetic.
3. Ni(CO)4 and [NiCl4]2- are diamagnetic and [Ni(CN)4]2- is paramagnetic.
4. Ni(CO)4 and [Ni(CN)4]2- are diamagnetic and [NiCl4]2- is paramagnetic.

X is the number of geometrical isomers exhibited by [Pt(NH3)(H2O)BrCl]. Y is the number of optically inactive isomer(s) exhibited by [CrCl2(ox)2]3-. Z is the number of geometrical isomers exhibited by [Co(NH3)3(NO2)3]. The value of X + Y + Z is .

The correct increasing order of spin-only magnetic moment values of the complex ions [MnBr4]2- (A), [Cu(H2O)6]2+ (B), [Ni(CN)4]2- (C) and [Ni(H2O)6]2+ (D) is :

1. A = B < D < C
2. C = D < B < A
3. C < B < D < A
4. A = B < C < D

The number of isoelectronic species among Sc3+, Cr2+, Mn3+, Co3+ and Fe3+ is ‘n’. If ‘n’ moles of AgCl is formed during the reaction of complex with formula CoCl3(en)2NH3 with excess of AgNO3 solution, then the number of electrons present in the t2g orbital of the complex is .

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

1. Both Statement I and Statement II are false
2. Statement I is true but Statement II is false
3. Both Statement I and Statement II are true
4. Statement I is false but Statement II is true