Let A = bmatrix1 & 2\\0 & 1 bmatrix and B = I + adj(A) + (adj A)2 + + (adj A)10. Then, the sum of all the elements of the matrix B is:
- -110
- 22
- -124
- -88
Answer
(4) -88
Solution
adj A = bmatrix1 & -2\\0 & 1 bmatrix ( adj bmatrixa & b\ & d bmatrix = bmatrixd & -b\\-c & a bmatrix )
(adj A)r = bmatrix1 & -2r\\0 & 1 bmatrix
B = r=010 bmatrix1 & -2r\\0 & 1 bmatrix = bmatrix11 & -110\\0 & 11 bmatrix ( 2(1 + 2 + + 10) = 110 )
Sum of elements = 11 - 110 + 0 + 11 = -88
Answer: (4)