A mass of 1 kg is kept on an inclined plane with 30 inclination with respect to horizontal plane and it is at rest initially. Then the whole assembly is moved up with constant velocity of 4 m/s. The work done by the frictional force in time 2 s is J. (Take g=10 m/s2)
- 20
- 25
- 30
- 10
Answer
(1) 20
Solution
[figure]
The assembly moves with constant velocity, the block is in equilibrium (no slipping).
Along the incline: f=mg 30 =1 10 12=5 N (up the incline)
Displacement of the block in 2 s: s=vt=4 2=8 m (vertically upward)
Angle between f (up the incline) and the vertical =90 -30 =60
Wf=fs 60 =5 8 12
Wf=20 J
Answer: (1)