A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is LA when it is at A and LB when it is at B, then [figure]
- LA = LB
- the relationship between LA and LB depends upon the slope of the line AB
- LA < LB
- LA > LB
Answer
(1) LA = LB
Solution
L = mv r , where r = perpendicular distance of the line of motion from O.
For every point on line AB, r = OC (same), and m, v are constant.
⇒ LA = mv(OC) = LB (same direction, along the z-axis)
Answer: (1)